gravitation questions and answers

Weight, W = mg, m = \(\frac{W}{g}\), m = \(\frac{9.8}{9.8}\) = 1 kg Question 5. So, when dropped from the same height a body reaches the ground quicker at the poles than at the equator. Question 4. A stone dropped from the roof of a building takes 4s to reach the ground. (e) Acceleration = -10 ms-2 or F = G × \(\frac{m_{1} m_{2}}{r^{2}}\) ……..(3) State the universal law of gravitation. ∴ New weight becomes 4 times. = M + \(\frac{10}{100}\)M = M + \(\frac{M}{10}\) = \(\frac{11M}{10}\) = 1.1 M What keeps the moon in uniform circular motion around the earth? [NCERT Exemplar] or D = \(\frac{g R^{2}}{G \frac{4}{3} \pi R^{3}}=\frac{3 g}{4 \pi G R}\), Question 6. Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2), Weight of an object is directly proportional to the mass of the earth and inversely proportional to the square of the radius of the earth, i.e., Answer: (d) The quantity G is universal constant of nature. Weight of a body ∝ \(\frac{M}{R^{2}}\) Then what will happen to your weight? i.e., First stone would take 3.16 s to reach the ground. Answer: This law states that every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to square of distance between them. ∴ For the second stone, Question 2. Answer: Velocity-time graph for the ball’s motion is shown in figure. Question 8. \(\frac{W_{m}}{W_{e}}=\frac{M_{m}}{M_{e}} \times \frac{R_{e}^{2}}{R_{m}^{2}}\) …. Answer: On the moon’s surface, the acceleration due to gravity is 1.67 ms-2. The radius of the earth is 6400 km and g = 10 m/s². Answer: Acceleration, g = – 9.8 m/s2 0 = 0.5 – 9.8t Question 3. CLASS 11 PHYSICS CHAPTER 8 GRAVITATION QUESTION ANSWERS, A star 2.5 times the mass of the sun and collapsed to a size of 12 km rotates with a It also implies that a body orbiting in space has zero weight with respect to a spaceship. Browse from thousands of Gravitation questions and answers (Q&A). mass of the moon, Mm = 7.4 × 1022 kg or – 0.25 = -19.6 h Gravitation Multiple Choice Questions & Answers for competitive exams. If it does, why does the earth not move towards the apple? Given m1 = 3 kg; m2 = 12 kg F = mg …(2) Isaac Newton. i.e., weight will be reduced to one-fourth of the original. At what place on the earth’s surface is the weight of a body minimum? Ratio will not change in either case because acceleration remains the same. radius of the earth, Re = 6400 km ∴ v = 0 + (-10) × 2 = -20 ms-1 The acceleration due to gravity is more at the poles than at the equator. Question 6. (c) At which point is the bal 1 at its maximum height? Question 1. Answer: New weight becomes 1.1 times. Question 16. If a satellite of mass m is revolving around the earth with distance rfrom centre, then total energy is Answer: (c) The satellite revolving around the earth has two types of energies. Answer: Question 19. h = 1.27 cm Answer: Question 4. A: Yes B: No. Do you agree with his hypothesis or not? Answer: Enjoy the videos and music you love, upload original content, and share it all with friends, family, and the world on YouTube. Because the value of acceleration due to gravity (g) on the moon’s surface is nearly l/6th to that of the surface of the earth. or, v2 – 02 = 2(-10) × (-40) (b) At which point is the bal 1 stationary? or, v = \(\sqrt{800}\) As the body falls back to the earth with the same velocity it was thrown vertically upwards. Define the standard kilogram. This will clear students doubts about any question and improve application skills while preparing for board exams. [NCERT Exemplar] the time taken by the second stone to reach the ground is one second less than that taken by the first stone as both the stones reach the ground at the same time. It will remain the same on the moon, i.e., 9.8 kg. Acceleration, a = g = 9.8 m/s2 Final speed, v = 0 Thus, equation (3) becomes, Question 1. Height of the building, h = ? Both C and D; [(Kg-m/Sec 2) = N] Q.19 Weight of free fall object is. TopperLearning’s Experts and Students has answered all of Gravitation of MAHARASHTRA Class 10 Physics questions in detail. Identical packets are dropped from two aeroplanes—one above the equator and other above the north pole, both at height h. Assuming all conditions to be identical, will those packets take same time to reach the surface of earth? Weight is not a constant quantity. Question 3. [NCERT Exemplar] The way the world works is exciting. Similarly, the force of attraction between the earth and the body Q is given by Question 5. In order that a body of 5 kg weighs zero at … And Radius of the earth, Re = 6.4 × 106 m. Question 7. How is gravitation different from gravity? Answer: Here, s = 100 m, u = 0 Answer: Q.17 Does the gravitational force same for two objects inside and outside the water? We know from Newton’s second law of motion that the force is the product of mass and acceleration. t1 = \(\frac{u}{g}\) …(1) QUESTION 6 (2002 EXAM) (a) Calculate the magnitude of the gravitational acceleration g at the Earth's surface, using Newton's second law and the law of universal gravitation. When hypothetically M becomes 4 M and R becomes \(\frac{R}{2}\). Question 2. [NCERT Exemplar] Answer: On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Question 4. Does the apple also attract the earth? Question 1. Answer: As u = 0, h1 = \(\frac{1}{2} g t_{1}^{2}\) Gravitational constant is numerically equal to the force of attraction between two masses of 1 kg that are separated by a distance of 1 m. It is different at different places. Molecules in air in the atmosphere are attracted by gravitational force of the earth. NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12, Extra Questions for Class 9 Science Chapter 10 Gravitation. For both the stones Do fluids possess weight? Differences between g andG. When r changes to 2r, the new weight is given by As we know s = ut + \(\frac{1}{2}\) gt2 This test will determine your knowledge of the subject. Very Short Answer Type Questions. The mass of the Sun is 2 x 10 30 kg and that of the Earth is 6 x 10 24 kg. (f) What is the bal l’s acceleration at point B? Gravitation Class 9 Extra Questions Short Answer Questions-I. Draw areal velocity versus time graph for mars. 3. Both the bodies fall with the same acceleration towards the surface of the earth. Let the mass, m3 = 0.5 kg be placed at a distance of ‘x’ m from m1, as shown in figure. Question 8. Answer The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force.The force acting between two objects is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Question 1. Access Answers to NCERT Class 9 Science Chapter 10 – Gravitation ( All In text and Exercise Questions Solved) Exercise-10.1 Page: 134. Mass of the earth, Me = 6 × 1024 kg Answered by Expert ICSE IX Physics Upthrust in Fluids, Archimedes' Principle and Floatation. The constant ‘G’ is universal because it is independent of the nature and sizes of bodies, the space where they are kept and at the time at which the force is considered. Zero. Free PDF download of Important Questions with solutions for CBSE Class 9 Science Chapter 10 - Gravitation prepared by expert Science teachers from latest edition of CBSE(NCERT) books. ∴ W = \(\frac{G M m}{r^{2}}\) We know that g = \(\frac{G M}{R^{2}}\) or M = \(\frac{g R^{2}}{G}\) Why does a body reach the ground quicker at poles than at the equator when dropped from the same height? Both stones will take the same time to reach the ground because the two stones fall from the same height. v = u + gt2 At the poles. It’s what keeps us safe on the ground, as opposed to floating up through the air. It is denoted by ‘g’. Answer: Answer: Question 2. Here are some practice questions that you can try. (2) Answer: Zero. Now, mass of the earth, Me = 6 × 1024 kg % Variation in the weight of a body = % Change in g = 0.7%. A stone is dropped from the top of a 40 m high tower. h2 = \(\frac{1}{2} g t_{2}^{2}\), Suppose gravity of earth suddenly becomes zero, then which direction will the moon begin to move if no other celestial body affects it? Answer: MCQ quiz on Gravitation multiple choice questions and answers on gravitation MCQ questions quiz on gravitation objectives questions with answer test pdf. ... plz answer this questions. A comprehensive database of gravitation quizzes online, test your knowledge with gravitation quiz questions. Question 21. It is applied to all the body present in universe It is constant of proportionality in Newton’s universal law of gravitation. Question 17. Get all questions and answers of Gravitation of MAHARASHTRA Class 10 Physics on TopperLearning. Answer According to question, M S = Mass of the Sun = 2×10 30 kg M E = Mass of the Earth = 6×10 24 kg R = Average distance between the Earth and the Sun = 1.5×10 11 m From Universal law of gravitation, Answer: Combining (1) and (2), we get Here, if the masses mx and m2 of the two bodies are of 1 kg and the distance (r) between them is 1 m, then putting m1 = 1 kg, m2 = 1 kg and r = 1 m in the above formula, we get The acceleration due to gravity does not depend upon the mass of the stone or body. What does a small value of G indicate? Solution: The universal law of gravitation states that every object in the universe attracts every other object with a force called the gravitational force. Gravitational force. Zero. The standard kilogram is the mass of a block of a platinum alloy kept at the international bureau of weights and measures near Paris in France. ⇒ t2 = \(\frac{98}{9.8}\) = 10 ∴ 49 = 0 × t + \(\frac{1}{2}\) × 9.8 × t2 Assume that g = 10 m/s2 and that there is no air resistance. Yes. Explain why all of them do not fall into the earth just like an apple falling from a tree. Thus, the packets will remain in air for longer time interval, when it is dropped at the equator. FQ = \(\frac{G \times M_{e} \times m_{2}}{R^{2}}\) ……. “Every body in the universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.” Let us consider two bodies A and B of masses m1 and m2 which are separated by a distance r. Then the force of gravitation (F) acting on the two bodies is given by Initial speed, u = 0.5 m/s Find the position of that point. We know that F = \(\frac{G M m}{r^{2}}\) as weight of a body is the force with which a body is attracted towards the earth, The tides in the sea formed by the rising and falling of water level in the sea are due to the gravitational force of attraction which the sun and the moon exert on the water surface in the sea. If the mass of a body is 9.8 kg on the earth, what would be its mass on the moon? = \(20 \sqrt{2}\)ms-1, Question 6. Question 10. Dividing equation (1) by (2), we get […] Define acceleration due to gravity. If you are a student of class 9 who is using NCERT Textbook to study Science, then you must come across Chapter 10 Gravitation. Comment. Question Answers, Page 134. Question 1. Question 11. Question 4. What will happen to the gravitational force between two bodies if the masses of one body is doubled? Where, R is the distance of the body from the centre of the earth. Question 7: Law of gravitation gives the gravitational force between (a) the earth and a point mass only t2 = u/g …(2) Initial velocity, u = 0 (d) What is the ball’s acceleration at point C? This hypothesis is not correct. As per the universal law of gravitation, the force of attraction between the earth and the body P is given by, Why can one jump higher on the surface of the moon than on the earth? These questions are quite useful to prepare the objective type questions for … Q1. part1, Page 1 So, both the stones will reach the ground at the same time when dropped simultaneously. Question 2. Kerala Plus One Physics Chapter Wise Questions and Answers Chapter 8 Gravitation Plus One Physics Gravitation One Mark Questions and Answers Question 1. It is different at different places on the surface of the earth. What is the source of centripetal force that a planet requires to revolve around the sun? From (1) and (2), we get t1 = t2 (3) Calculate the height of the building. where Me = mass of earth and Re = radius of earth. A small value of G indicates that the force of gravitational attraction between two ordinary sized objects is a very weak force. Suppose the mass of the moon is Mm and its radius is Rm. Therefore, the body appears to be floating weightlessly. Fill in the blanks : _____ of an object is the force of gravity acting on it.. Class 9 - Physics - Gravitation . 0 = u – gt1 Then force acting on m3 due to m1, is equal and opposite to the force acting on m3 due to m2. Answer: Question 15. Question 20. Is weight a force? Calculate its speed after 2 s. Also find the speed with which the stone strikes the ground. The earth is acted upon by gravitation of sun, even though it does not fall into the sun. Answer: Question 5. When M changes to new mass M’ Free Question Bank for NEET Physics Gravitation. Weight is the force of gravity acting on the body. Find out the ratio of time they would take in reaching the ground. [NCERT Exemplar] g = 9.8 ms-2, h = 49 m, t = 2.16 s, u = ? Enter OTP. 1. But we know, acceleration ∝ 1/m. Previous: Contents: Next: State the universal law of gravitation. ⇒ t = \(\sqrt{10}\) = 3.16 s Yes, fluids have weight. Our online gravitation trivia quizzes can be adapted to suit your requirements for taking some of the top gravitation quizzes. ⇒ Average density of the earth, D = \(\frac{\text { Mass }}{\text { Volume }}=\frac{g R^{2}}{G \times V e}\) And the mass of body Q=m2 F ∝ m,1m2 and F ∝ \(\frac{1}{r^{2}}\) Two planets of radii R 1 and R 2 have the same density. Would reach the ground required point is the bal 1 at its maximum height AIIMS... Quizzes can be adapted to suit your requirements for taking some of the object × gravitational acceleration B: gravitation... Which he threw the second stone was thrown downward with a speed of m/s. 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